E F
10 ft 10
D C D C
Figure 2a: Before updating Figure 2b: After updating 11.3.1.2. Division by poly-lines
This technique is applicable when multi-segmented division is required (as given in Figure 3a). According to the picture given below, the polygon ABCD needs to be segmented in several subparts. Such as AEGF, HIJB, MNDC.
G I
A F H B
E J
M N
D C C
To find out the actual points, one needs to apply the bisecting radius method (as given in Figure 3b). Suppose the user wants to split a polygon AEGF from ABCD polygon. To get the point G, two circles will be drawn taking E and F as their corresponding centers. The bisecting point of these two circles will be the new vertex G (as shown in the figure). After getting the point G, one needs to join GE and GF to get the resultant polygon (AEGF).
Figure 3b: Getting the bisecting point
11.3.1.3. Division by parallel lines
This technique is very useful when users require a parallel division with respect to any side of the older polygon (as shown in Figure 4). According to the figure, ABCD is the parent polygon and EFCB is the child one. MUS will need to calculate two different points E and F along the line BA and CD respectively. MUS will also need to join the points E and F to get the line EF for the resultant polygon (EFCB).
Figure 4: After updating ABCD with parallel line
11.3.1.4 Division by perpendicular lines
This technique is applicable when perpendicular deviation is required (as shown in Figure 5). As shown in the figure given below, the point E is 8 ft. far from the point D along the line DA and the point G is 12 ft. far from the point C along with CD. Then, one will draw a perpendicular EF at the point E on the line DA. The line EF is 6 ft. long. FG will be joined. Now, one gets the resultant polygon EFGD.
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