Sat 2015 Practice Test #1 Answer Explanations



Yüklə 1,86 Mb.
Pdf görüntüsü
səhifə32/47
tarix11.09.2023
ölçüsü1,86 Mb.
#121682
1   ...   28   29   30   31   32   33   34   35   ...   47
sat-practice-test-1-answers

The correct answer is 7. 
Subtracting the left and right sides of 
[

y
ơIURPWKHFRUUHVSRQGLQJVLGHVRI[
+ 2
y
ơJLYHV
(
[
+ 2
y
)
 
ơ
[


ơơơ
)
ZKLFKLVHTXLYDOHQWWR
y
ơ
6XEVWLWXWLQJơIRU
y
in 
[

y
ơJLYHV[ơ ơZKLFKLV
equivalent to 
[ ơơơ
QUESTION 19 
_
The correct answer is 5
4 or 0.8.
By the complementary angle
relationship for sine and cosine, sin(
[r FRVrơ[
°). Therefore, 
_
FRVrơ[
°) = 45
(LWKHUWKHIUDFWLRQRULWVGHFLPDOHTXLYDOHQW
may be gridded as the correct answer. 
Alternatively, one can construct a right triangle that has an angle of 
_
mea sure 
[
° such that sin(
[
°) = 45 
DVVKRZQLQWKHƮJXUHEHORZZKHUH
sin(
[
°) is equal to the ratio of the length of the side opposite the angle 
_
measuring 
[
° to the length of the hypotenuse, or 45 .
90
°
– 
x
°


x
°
90
°
Since two of the angles of the triangle are of measure 
[rDQGrWKH
WKLUGDQJOHPXVWKDYHWKHPHDVXUHrơrơ[r rơ[
°. From 
WKHILJXUHFRVrơ[
°), which is equal to the ratio of the length of 
the side 
DGMDFHQWWRWKHDQJOHPHDVXULQJrơ[
° to the hypotenuse, 
_
is also 45 .















_
QUESTION 20 
The correct answer is 100.
Since 
D
= 5
Ƥ
2, one can substitute 5
Ƥ
2 for 
D
in 2
D

Ƥ
2
JLYLQJ
Ƥ
2 = 
Ƥ
2
6TXDULQJHDFKVLGHRI
Ƥ
2 = 
Ƥ
2
[
gives 
Ƥ
2)
2
= (
Ƥ
2
[
)
2
ZKLFKVLPSOLƮHVWR
2
(
Ƥ
2)
2
= (
Ƥ
2
[
)
2
, or 
_
[
. This gives 
[ 7RYHULI\VXEVWLWXWHIRU[
and 5
Ƥ
2 for 

D
in the equa

tion 2
D


Ƥ
2
[

, which yiel

ds 2(5

Ƥ
2) = 
Ƥ
(
WKLVLVWUXH
since 2(5
Ƥ
2)
Ƥ
2 and 
Ƥ
(
Ƥ
2
Ƥ 
Ƥ
2.
6HFWLRQ0DWK7HVWs&DOFXODWRU
QUESTION 1 
Choice B is correct.
2QWKHJUDSKDOLQHVHJPHQWZLWKDSRVLWLYH
slope represents an interval over which the target heart rate is strictly 
increasing as time passes. A horizontal line segment represents an 
interval over which there is no change in the target heart rate as 
time passes, and a line segment with a negative slope represents 
an interval over which the target heart rate is strictly decreasing as 
WLPHSDVVHV2YHUWKHLQWHUYDOEHWZHHQDQGPLQXWHVWKHJUDSK
consists of a line segment with a positive slope followed by a line 
segment with a negative slope, with no horizontal line segment in 
between, indicating that the target heart rate is strictly increasing 
then strictly decreasing. 
Choice A is incorrect because the graph over the interval between 
DQGPLQXWHVFRQWDLQVDKRUL]RQWDOOLQHVHJPHQWLQGLFDWLQJD
period in which there was no change in the target heart rate. Choice C 
LVLQFRUUHFWEHFDXVHWKHJUDSKRYHUWKHLQWHUYDOEHWZHHQDQG
65 minutes consists of a line segment with a negative slope followed 
by a line segment with a positive slope, indicating that the target heart 
rate is strictly decreasing then strictly increasing. Choice D is incorrect 
EHFDXVHWKHJUDSKRYHUWKHLQWHUYDOEHWZHHQDQGPLQXWHV
contains horizontal line segments and no segment with a negative 
slope. 
QUESTION 2 

Yüklə 1,86 Mb.

Dostları ilə paylaş:
1   ...   28   29   30   31   32   33   34   35   ...   47




Verilənlər bazası müəlliflik hüququ ilə müdafiə olunur ©genderi.org 2024
rəhbərliyinə müraciət

    Ana səhifə