Malla Reddy College of Engineering and Technology (MRCET)
Department of EEE ( 2017-18 )
Electrical Circuits EEE
Example Problems:
1) Find the Req for the circuit shown in below figure.
fig(a)
Solution:
To get Req we combine resistors in series and in parallel. The 6 ohms and 3 ohms resistors are in
parallel, so their equivalent resistance is
Also, the 1 ohm and 5ohms resistors are in series; hence their equivalent resistance is
Thus the circuit in Fig.(b) is reduced to that in Fig. (c). In Fig. (b), we notice that the two 2 ohms
resistors are in series, so the equivalent resistance is
This 4 ohms resistor is now in parallel with the 6 ohms resistor in Fig.(b); their equivalent
resistance is
The circuit in Fig.(b) is now replaced with that in Fig.(c). In Fig.(c), the three
resistors are in
series. Hence, the equivalent resistance for the circuit is
Malla Reddy College of Engineering and Technology (MRCET)
Department of EEE ( 2017-18 )
Electrical Circuits EEE
2) Find the Req for the circuit shown in below figure.
Solution:
In the given network 4 ohms, 5 ohms and 3 ohms comes in series then equivalent resistance is
4+5 + 3 = 12 ohms
Dostları ilə paylaş: