Abc uchburchakning ab va bc tomonlarida mos ravishda e va f nuqtalar shunday tanlab olinganki b uchidan boshlab hisoblaganda (ab va bc tomonlarini ) : nisbatda bo’ladi

#1.ABC uchburchakning AB va BC tomonlarida mos ravishda E va F nuqtalar shunday tanlab olinganki B uchidan boshlab hisoblaganda (AB va BC tomonlarini ) 2:3 nisbatda bo’ladi. Agar ABC uchburchakning yuzi 75 ga teng bo’lsa, AEF uchburchakning yuzini toping.
A) 16 B)20 C) 15 +D) 18
#2.a ning qanday qiymatlarida uzunliklari mos ravishda a+2; 4 va 2a-1 bo’lgan kesmalardan uchburchak yasash mumkin?
+A) (1;7) B) (0;5) C) (1;8) D) (0;7)
#3.Agar rombning bir dioganalini 50% ga kamaytirib, ikkinchi dioganalini 2 marta uzaytirilsa, rombning yuzi qanday o’zgaradi?
+A) O’zgarmaydi B) 50% ga ortadi C) aniqlab bo’lmaydi D) 50% ga kamayadi
#4.Teng yonli trapetsiyaning katta asosi 25 sm va peremetri 55 sm. Agar trapetsiyaning dioganali uning o’tkir burchagini teng ikkiga bo’lsa, trapetsiyaning o’rta chizig’ini toping.
A) 16sm B) 18 sm +C) 17,5 sm D) 17 sm
#5. Agar va bo`lsa, ni toping.
+A) B) C) D) 1
#6. Chizmada davri ga teng bo`lgan funksiya grafigi berilgan. Bunga ko`ra ning qiymatini toping.

A) 2 B) -2 C) -1 +D) 0
#7. ning nechta qiymatida son ham natural bo`ladi?
A) 1 B) 2 C) 3 +D) 4
#8. bo`lsa,
+A) 1 B) C) D)
#9. tenglamaning kesmadagi barcha yechimlari yig`indisini toping.
A) +B) C) D)
#10. funksiyaning aniqlanish sohasini toping.
A) B) +C) D)
#11. va to‘g‘ri chiziqlarning kesishish nuqtasi va nuqtadan o‘tuvchi to‘g‘ri chiziq tenglamasini yozing.
A) B) +C) D)
#12. va bo`lsa, ni m va n orqali ifodalang.
A) B) +C) D)
#13. Hisoblang:
+A) B) 23 C) 44 D) 45
#14. a_n= - 3n²+18n+1 (n-natural) formula bilan berilgan ketma ketlikning nechanchi hadi eng katta qiymatga ega bo`ladi?
+A) 3 B) 2 C) 6 D) 8
#15. funksiyaning aniqlanish sohasini toping.
A) (-1; 3) +B) [-1; 3) C) (- ;3) D) (- ;-1]
#16. tenglamaning ildizlari yig`indisini toping
+A) 6 B) 5 C) 4 D) 3
#17. Agar va bo’lsa, b ni a orqali ifodalang.
A) B) C) +D)
#18. Kasrning maxrajini irrasionallikdan qutqaring.
A) B) C) +D)
#19. Ushbu tengsizlikni qanoatlantiruvchi butun sonlar nechta?
+A) B) 1 C) 2 D) 3
#20. Tenglamani yeching.
+A) -1 B) 3 C) -1; 3 D) 1
#21. Agar bo`lsa, tengsizlikning eng kichik butun yechimini toping.
A)1 +B)-1 C)-5 D)0
#22. funksiyaning (6;0) nuqtadan o`tuvchi boshlang`ich funksiyasini toping.
A) +B) C) D)
#23. 11300 ning 36% i va 8400 ning 28% ining yig’indisi shu sonlar yig’indisining 40% idan qanchaga kam?
+A)1460 B)1360 C)1560 D)1465
#24. Mahsulotning narhi ketma-ket ikki marta 100% dan oshirildi. Keyinchalik bu mahsulotga talabning kamligi tufayli uning narhi 20% ga kamaytirildi. Mahsulotning keyingi bahosi dastlabki bahosiga qaraganda qanday o’zgargan?
A) 1,8 marta ortgan B) 1,2 marta ortgan
C) 3,2 marta kamaygan +D) 3,2marta ortgan
#25. Tenglamani yeching.
A) , B) , + C) , D) ,
#26. tenglama kesmada nechta ildizga ega ?
A)1 +B)2 C)3 D)4
#27. ABC uchburchakning AB, BC vа CA tоmоnlaridа shundаy K vа N nuqtаlar оlinаdiki. gа vа gа tеng bo’lаdi. ABC uchburchakning yuzi 18 gа tеng. АKN uchburchakning yuzini toping.
+А) 4 B) 6 C) 9 D) 2
#28. Uchburchakning ichidаgi M nuqtаdаn uning tоmоnlarigа pаrаllеl to’g’ri chiziqlar o’tkаzildi. Nаtijаdа bеrilgаn uchburchakning ichidа M nuqtadа umumiy uchgа egа, yuzlari esа 3:12 vа 27 gа tеng bo’lgan uchtа uchburchak hоsil bo’lаdi. Bеrilgаn uchburchakning yuzini toping.
А) 84 B) 72 +C) 108 D) 144
#29. Pеrimеtri 84 sm bo’lgan uchburchakning аsоsigа pаrаllеl qilib o’tkаzilgаn to’g’ri chiziq undа pеrimеtri 42 sm gа, yuzi 27 sm² gа tеng uchburchak аjrаtаdi. Bеrilgаn uchburchakning yuzini toping.
А) 54 sm² +B)108sm² C)135 sm² D) 81sm²
#30. Diаgоnаllari 6 vа 8 gа , ular оrаsidаgi burchak 60⁰ gа tеng bo’lgan pаrаllеlоgrаmmning pеrеmеtrini toping.
А) +B) C) D)
#31. Asoslari 12 va 16 ga, o’tmas burchagi 120⁰ ga teng bo’lgan teng yonli trapetsiyaning yuzini hisoblang.
A) B) +C) D) 14
#32. va mos ravishda uchburchak, qavariq to’rtburchak va beshburchak tashqi burchaklarining yig’indilari. Quyidagi munosabatlardan qaysi biri o’rinli.
A) B)
C) +D)
#33. Aylananing uzunligi 8 ga teng. Uzunligi uning 90° li yoyiga teng bo'lgan aylananing radiusini toping.
+A) l B)2 C) D)3
#34. Eng kichik burchagi 50⁰ bo’lgan biror qavariq ko'pburchakning ichki burchaklari, ayirmai 10⁰ bo’lgan arifmetik progressiyani tashkil qiladi. Bu ko'pburchakning tomoni eng ko’pi bilan nechta bo’lishi mumkin.
+A) 3 ta B) 27 ta C) 24 ta D)5 ta
#35. tengsizlikning butun sonlardan iborat yechimlari nechta
A)2 +B)3 C)4 D)5
#36. Tengsizlikning eng kichik musbat butun yechimini toping.
A)6 B)3 C)5 +D)2
#37. Ushbu funksiyaning aniqlanish sohasiga tegishli barcha butun sonlarning yig’indisini toping.
A)3 +B)4 C)5 D)6
#38. tenglamani yeching
A)56 B)48 +C)60 D)54
#39.Sakkizta haddan iborat arifmetik progressiyaning toq o’rindagi hadlari yig’indisi 168 ga, juft o’rindagi hadlar yig’indisi 200 ga teng.Shu progressiyaning oltinchi hadini toping.
A)58 B)42 C)66 +D)50
#40. sina + cosa=1.35 bo’lsa, a burchakka mos keluvchi nuqta qaysi chorakda joylashgan?
+A) 1 chorakda B) 2 chorakda C) 3 chorakda D)4 chorakda