Power electronics digital notes b. Tech III year


Figure: 2.3 Single phase half wave rectifier with R load with waveforms



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power electronics digital notes

Figure: 2.3 Single phase half wave rectifier with R load with waveforms 
The load current i
0
flows throug
h ‘R’
the waveforms for voltage & current are as shown above. 
As load is resistive, 
Output current is given as, 
 
Hence shape of output current is same as output voltage 
As T1 conducts only in positive half cycle as it is reversed bias in negative cycle, the ripple frequency of 
output voltage is- 
fripple= 50 Hz (supply frequency) 
Average output voltage is given as


57 | 
P a g e
 
i.e Area under one cycle. 
Therefore T=2π&Vo(ωt) = Vm sinωt from α to π& for rest of the period Vo(ωt)=0
 
Power transferred to load, 
 
Thus, power & voltage can be controlled by firing angle. 
 
Single Phase Half Wave Controlled Rectifier with 
‘RL’
 load: 
Figure: 2.4 Single phase half wave rectifier with RL load with waveforms 


58 | 
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Figure above shows the single phase half wave rectifier with RL Load. 

Normally motors are inductive loads 
L= armature of field coil inductance 
R= Resistance of coil. 

In positive half cycle, SCR starts conduction at firing angle “α”.

Drop across SCR is small & neglected so output voltage is equal to supply voltage. 

Due 
to ‘R
L
’ load, current through SCR increases slowly.

At ‘π’, supply voltage is at zero where load current is at its max value.

In positive half cycle, inductor stores energy & that generates the voltage. 

In negative half cycle, the voltage developed across inductor, forward biases SCR & maintains its 
conduction. 

Basically with the property of inductance it opposes change in current. 

Output current & supply current flows in same loop, so all the time i
o
=i
s


After π the energy of inductor is given to mains & there is flow of ‘io’. The energy reduces as if gets 
consumed by circuit so current also reduces. 

At ‘β’ energy stored in inductance is finished, hence ‘i
o
’ becomes zero & ‘T1’ turns off.

‘i
o
’ becomes zero from ‘β’ to ‘2π+α’ hence it is discontinuous condu
ction. 
The average output voltage V
0


π
α
β
I


π
α
β
RMS load voltage V
0r




59 | 
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