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Hisoblang a − b −2 c 1 d 2
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tarix | 22.01.2023 | ölçüsü | 25,67 Kb. | | #98973 |
| TEST-106
TEST _ 106
2 + 2x − 3 = 3 tenglama ildizlari yig’indisini toping. A)0 B)1 C)−1 D)5
6 ga bo’linganda 4 , 8 ga bo’linganda 6 , 12 ga bo’linganda 10 qoldiq qoladigan 340 gacha nechta natural son bor ? A)8 B)13 C)14 D)15
tenglamalar sistemasidan x + y ni toping. A)3 B)7 C)5 D)4
Tengsizlikni barcha butun manfiy yechimlari ko’paytmasini toping. + + ≤ 0 A)−150 B)−120 C)−100 D)−80
Hisoblang A)− B)−2 C)1 D)2
Bir qishloqda qarama – qarshi yo’nalishda 2 velosipedchi bir vaqtda yo’lga chiqdi. Birinchi velosipedchining tezligi v km/soat bo’lib u ikkinchisining tezligidan 1.5 martta kam. Ular orasidagi masofa necha soatdan so’ng 45 km bo’ladi ? A) B) C)2.5v D)
∙ : ni soddalashtiring. A)x B)1 C)x + 1 D)x – 1
likni butun yechimi nechta ? ≤ 0 A)2 B)cheksiz ko’p C)3 D)4
; ; sonlariga bo’linganda bo’linma butun son chiqadigan eng kichik natural sonni toping. A)120 B)48 C)24 D)12
funksiyaning aniqlanish sohasini toping. A) B) C)[−2;∞) D)
Y ning qandey musbat qiymatida 8 – 6x + 9 = 0 tenglamaning bir ildizi ikkinchisining kvadratiga teng bo’ladi ? A)1 B)2 C)0. D)0.5
= 4 – 4x + 7 + 3 ko’pxadi uchun 1. Ko’pxadning bosh koeffitsienti 4 ga teng. 2.Ko’pxadning ozod xadi 3 ga teng. 3. Ko’pxadning darajasi 4 ga teng. 4. Ko’pxad koeffitsientlari yig’indisi 9 ga teng. Jumlalardan nechtasi to’g’ri? A)1 B)2 C)3 D)4
ning toq bo’luvchilar sonini toping. A)234 B)18 C)13 D)216
tenglamaning ildizlari yig’indisini toping. A)0 B)−1 C)4 D)1
2 va tenglamaning ildizlari bo’lsa + + ni toping. A)4 B)6 C)5 D)7
+ 18 – 3 = 6 tenglamani yeching. A)−8 B)−10 C)−6 D)−4
= 5 tenglama ildizlari ayirmasi quidagilardan qaysi biriga teng bo’lishi mumkin ? A)2 B)−3 C)4 D)−2
ni hisoblang. (bu yerda -a sonining butun qismi) A)169 B)121 C)144 D)256
Arifmetik progressiyaning n ta hadi yig’indisi = 2 formula bilan ifodalanadi. + – d ni hisoblang. A)35 B)32 C)48 D)38
< 5 tengsizlik nechta butun yechimga ega ? A)17 B)16 C)15 D)18
A)5 B)3 C)4 D)2
a>0 , b>0 va a + b = 12 bo’lsa , ab ning eng katta qiymatini toping. A)60 B)72 C)66 D)108
− x + a + 1 = 0 tenglamaning ildizlari va bo’lib , ∙ + ∙ = 15 tenglik o’rinli bo’lsa , a ni toping. A)1 B)2 C)3 D)4
= + 3 + 2x + 3 ko’pxadni x + 3 ga bo’lgandagi qoldiqni toping. A)−9 B)−6 C)−3 D)−4
shartni qanoatlantiruvchi geometric progressiyaning dastlabki to’rtta hadini yig’indisini toping. A)13 B)14 C)15 D)16
; − ; ; − ketma – ketlikning umumiy xadi formulasini ko’rsating. A) = B) = C) = D) =
: a ifodaning a= − da hisoblang. A) B)− C)36 D)− 6
a , b , c manfiy butun sonlar bo’lib , > > tengsizlik bajarilsa , − + ifodani soddalashtiring. A)−2a B)−2a – 2c C)0 D)b – a
− = 0 tenglama ildizlari kvadratlari yig’indisini toping. A)18 B)17 C)6 D)33
arifmetik progressiyada =2013 , =2001 bo’lsa , ni toping. A)1346 B)1344 C)1350 D)1354
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