1. Nechanchi hadidan boshlab -8; 4; -2; geometrik progressiya hadlarining absolyut qiymati 0,001 dan kichik bo’ladi?

Geometrik progressiya.
1.Nechanchi hadidan boshlab -8; 4; -2; ... geometrik progressiya hadlarining absolyut qiymati 0,001 dan kichik bo’ladi?
A) 16 B) 12 C) 15 D) 14 E) 13
2.Geometrik progressiya hadlari uchun b₁ b₃ · · · b₁₃ = b₂ b₄ · · · b₁₄ ·128 tenglik o’rinli bo’lsa, b₁ ni toping.
A)128 B) 64 C) 32 D) 256 E) aniqlab bo’lmaydi
3.Agar geometrik progressiyaning dastlabki 4 ta hadiga mos ravishda 1; 1; 4 va 13 sonlarini qo’shsak, ular arifmetik progressiyani tashkil etadi. Geometrik progressiyaning maxrajini toping.
A)2 B) -2 C) 3 D) -3 E) 4
4.Ikkinchi hadi 6 ga teng, birinchi uchta hadining yig’indisi 26 ga teng o’suvchi geometrik progressiyaning uchinchi va birinchi hadlari ayirmasini toping.
A)15 B) 16 C) 14 D) 13 E) 12
5.Agar geometrik progressiyada b₁ + b₉ =5 va b₂₁ + b₂₉ = 17 bo’lsa, b₄ · b₆ ni toping.
A) 4 B) 3 C) 2 D) 1 E) 6
6.Hadlari musbat bo’lgan geometrik progressiyaning birinchi va uchinchi hadi ko’paytmasi 4 ga, uchinchi va beshinchisiniki esa 64 ga teng.Progressiyaning ikkinchi, to’rtinchi va oltinchi hadlari yig’indisini toping.
A) 40 B) 44 C) 42 D)46 E) 38
7.3 va 19683 sonlari o’rtasiga 7 ta shunday musbat sonlar joylashtirilganki, hosil bo’lgan to’qqizta son geometrik progressiya tashkil etadi.5-o’rinda turgan son nechaga teng?
A)243 B)343 C) 286 D) 729 E) 442
8.Geometrik progressiyaning dastlabki uchta hadi yig’indisi −26 ga, dastlabki to’rtasiniki esa −80 ga teng. Agar shu progressiyaning birinchi hadi −2 ga teng bo’lsa, uning maxraji qanchaga teng bo’ladi?
A) 3 B) −3 C) −2 D) 2 E) 4
9.Geometrik progrogressiyaning maxraji −2 ga, dastlabki beshta hadining yig’indisi 5,5 ga teng. Progressiyaning beshinchi hadini toping.
A) 4 B) −8 C) 8 D) −16 E)16
10.Ishorasi almashinuvchi geometrik progressiyaning birinchi hadi 2 ga, uchinchi hadi 8 ga teng. Shu progressiyaning gastlabki 6 ta hadining yig’indisini toping.
A) 20 B) -20 C) -42 D) 42 E)-64
11.O’suvchi geometrik progressiyaning dastlabki to’rtta hadi yig’indisi 15 ga, undan keyingi to’rttasiniki esa 240 ga teng. Shu progressiyaning dastlabki oltita hadi yig’indisini toping.
A) 31 B) 48 C) 63 D) 127 E)114
12.Agar geometrik progressiyada S_k −S_k-1 =64, va S_k+1 −S_k = 128 bo’lsa, uning maxraji qanchaga teng bo’ladi?
A) 2 B) 2,2 C) 1,8 D) 2,4 E) 1,6
13.Tenglamani yeching. 1 − x + x₂ − x₃+ · · · + x₈ − x₉= 0

1. 
   10 B) 1 C) −1; 1 D) −1 E) −1; 10
   

14.Oltita haddan iborat geometrik progressiyaning dastlabki uchta hadining yig’indisi 168 ga, keyingi uchtasiniki esa 21 ga teng. Shu progressiyaning maxrajini toping.
A) 1/4 B) 1/3 C) 1/2 D) 2 E) 3
15.Agar hadlari haqiqiy sondan iborat bo’lgan o’suvchi geometrik progressiyaning birinchi uchta hadi yig’indisi 7 ga, ko’paytmasi 8 ga teng bo’lsa, shu progressiyaning beshinchi hadini toping.
A) 6 B) 32 C) 12 D) 16 E)20
16.Geometrik progressiyaning dastlabki oltita hadi yig’indisi 1820 ga, maxraji esa 3 ga teng.Shu progressiyaning birinchi va beshinchi hadlari yig’indisini toping.
A) 164 B) 246 C) 328 D) 410 E) 492
17.Geometrik progressiyaning ikkinchi hadi 2 ga, beshinchi hadi 16 ga teng. Shu progressiyaning dastlabki oltita hadi yig’indisini toping.
A) 81 B) 72 C) 65 D) 64 E) 63
18.Geometrik progressiyaning oltinchi va birinchi hadi ayirmasi 1210 ga, maxraji 3 ga teng.Shu progressiyaning dastlabki beshta hadi yig’indisini toping.
A) 610 B) 615 C) 600 D) 605 E) 608
19.Cheksiz kamayuvchi geometrik progressiyaning hadlari yig’indisi 9 ga, maxraji esa 1/3ga teng. Uning birinchi hamda uchinchi hadlari ayirmasini toping.

20. 
    Cheksiz kamayuvchi geometrik progressiyaning yig’indisi 56 ga, hadlari kvadratlarining yig’indisi esa 448 ga teng. Progressiyaning maxrajini toping.
    

1. 
   0,75 B) 0,8 C) 0,25 D) 0,5 E) 0,85
   

20. 
    hisoblang.
    

1. 
   0,3 B) 0,4 C) 0,5 D) 0,6 E) 0,7
   

22.Cheksiz kamayuvchi geometrik progressiya hadlarining yig’indisi uning dastlabki ikkita hadi yig’indisidan 2 ga ko’p. Progressiyaning birinchi hadi 4 ga teng. Shu progressiyaning hadlari yig’indisini toping.
A) 2 13 B) −4 C) 4 D) 8 E) 6
23.Hisoblang:

24. 
    Cheksiz kamayuvchi geometrik progressiyaning birinchi hadi 2 ga, hadlarining yig’indisi esa 5 ga teng. Shu progressiyaning hadlari kvadratlaridan tuzilgan progressiyaning hadlari yig’indisini toping.
    

1. 
   6,25 B) 6,5 C) 5,75 D) 6,75 E) 5,85
   

24. 
    Cheksiz kamayuvchi geometrik progressiyaning hadlari yig’indisi 1,6 ga, ikkinchi hadi −0, 5 ga teng. Shu progressiyaning uchinchi hadini toping.
    

26.b_n=3*2ⁿ geometrik progressiya dastlabki 6
ta hadi yig’indisi? A) 376 B) 377 C) 378 D) 380
27.Geometrik progressiyada 1000 ta had bor. Juft o‘rindagi hadlar yig’indisi a, toq o‘rindagi hadlar yig’indisi b bo‘lsa, progressiya maxrajini toping.

28. 
    Geometrik progresiyaning dastlabki 10 ta hadi yig’indisi m ga, keyingi 10 ta hadi yig’indisi n ga teng bo‘lsa, progressiya maxrajini toping.
    

29.O‘suvchi geometrik progressiya birinchi va oxirgi hadi yig’indisi 66 ga, ikkinchi va oxiridan oldingi had ko‘paytmasi esa 128. Agar jami hadlar yig’indisi 126 bo‘lsa, uning nechta hadi bor?
A) 6 B) 7 C) 8 D) 9
30.1; 3; 7; 15; … ketma-ketlikning 100 – hadini
toping. A) 2¹⁰⁰+1 1 B) 2¹⁰⁰-1 C) 2¹⁰¹-1  1 D) 2¹⁰¹+1