Article in Proceedings of the American Mathematical Society · October 005 doi: 10. 2307/4097907 citations reads 10 72 author



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Lemma 1. Let P ≥ 10 and assume the above notation. Then

    1. (1 ≤ i ≤ 20).

Furthermore, if u ≥ 1, we have

    1. .

Proof. To prove (2.2), we refer to the theorem in Thanigasalam [13] for the case i = 20 and then apply the iterative method in Vaughan [14] to deduce the remaining cases (see the discussion pertaining to k = 7 on pp. 455–459 in [14]).
We deduce (2.3) from (2.2) by a simple version of the circle method. We write (2.4) N = M(Q,P7), n = [0,1] \N, and N(q,a) = M(q,a;Q,P7), where Q = P1/9. For α ∈n, Lemma 2.1 in Kawada and Wooley [7] yields

    1. .

Combining (2.1), (2.2), and (2.5), we obtain



Suppose now that α ∈N(q,a) ⊂N. By Lemmas 6.1 and 6.3 in Vaughan [15] ,
q −1/7P(1 + N|α a/q|)−1, if j = 1,
λ
g α;
q−1/7Pλj, if 2 ≤ j ≤ 10,
whence
.
We deduce that
(2.7)
The desired bound follows from (2.4), (2.6), and (2.7).
2.2. Exponential sum estimates.
Lemma 2. Let α be real, let ξm be complex numbers with |ξm|≤ τ(m)c, and define
(2.8) ,
with ψ(n,z) given by (1.5). Suppose that M P11/20, z p2P/M, and that there exist integers a and q satisfying
(2.9) 1 ≤ q Q, (a,q) = 1, |a| < QP−7,
with Q P. Then
(2.10) ,
where Ψ(α) = q + P7|a| and L = logP. In particular, we have
(2.11) .
Proof. (2.10) is the case k = 7 of Lemma√ 5.6 in Kumchev [9]. (2.11) follows from
(2.10) on choosing M = 1 and z = 2P.
Lemma 3. Let 1/192 < ρ < 1/141 and let α be a real number such that no integers a and q satisfy (2.9) with Q = P1/4. Let S(α) be defined by (2.8) and suppose that
z P1−128ρ and M P(7−15ρ)/13.
Then
(2.12) .
Proof. This follows from the results in §3 of [9]. Let Q = P(49−14ρ)/13. By Dirichlet’s theorem on diophantine approximation, there exist integers a and q satisfying
(2.13) 1 ≤ q Q, (a,q) = 1, |a| < Q−1.
By assumption, a and q must also satisfy
(2.14) q + P7|a| > P1/4.
When z P1−130ρ, (2.13) and (2.14) suffice to deduce (2.12) from Lemma 3.3 in [9]. When P1−130ρ < z P1−128ρ, we recall Buchstab’s identity
(2.15) ψ(n,z2) = ψ(n,z1) − X X ψ(k,p) (2 ≤ z1 < z2).
z1p2 n=pk
Applying (2.15) with z1 = P1−130ρ and z2 = z, we obtain
S(α) = S1(α) − S2(α),
where
.
We can now use Lemma 3.3 in [9] to bound S1(α) and Lemma 3.1 in [9] ( with
(m,n) = (mk,p)) to bound S2(α).
2.3. Estimates for sums over integers free of small prime divisors. In this section, we prepare some asymptotic estimates for exponential sums over numbers free of small primes.
Lemma 4. Let 2 ≤ z y zc, let ψ(n,z) be defined by (1.5), and let ω(u) be the continuous solution of the differential delay equation
(((u)) 0 = ω(u − 1), if u > 2,
ω(u) = u−1, if 1 < u ≤ 2.
Let β be a real number, with |β|≤ y−7(logy)B. Then for any A > 0,
,
the implied constant depending at most on A and B. Here, γ is Euler’s constant and .
Proof. When β = 0, this follows from (1.7) in de Bruijn [2] and de la Vall´ee Poussin’s form of the prime number theorem (see §18 in Davenport [1]). The general case follows from the case β = 0 by partial summation.
Lemma 5. Let 2 ≤ z y zc, let ψ(n,z) be defined by (1.5), and let a and q be integers, with (a,q) = 1 and 1 ≤ q ≤ (logy)B. Then for any A > 0,
,
the implied constant depending at most on A and B.
Proof. This is a generalization of the Siegel–Walfisz theorem. By a variant of (3) in §20 of Davenport [1], it suffices to show that
(2.16) ,
for every nonprincipal character χ mod q. When z y1/2, (2.16) follows by partial summation from (3) in §22 of [1]. When z < y1/2, we apply Buchstab’s identity in the reverse. By (2.15) ,
(2.17) .
The first sum on the right of (2.17) can be estimated as before and the second sum is bounded above by
,
the maximum being over all pairs M,M0 with z M < M0 ≤ min(2M,y). Since this quantity can also be estimated by means of (3) in §22 of [1], the desired result follows.

  1. Proof of Theorem 1

Let n be a large even integer and set

    1. and Pj = Pλj (1 ≤ j ≤ 23),

where λ1,...,λ22 are the exponents defined in §2.1 and λ23 = 1. We aim to prove that the set

contains an integer that can be represented as the sum of 23 seventh powers of primes. If m is a natural number, we denote by r(m) the number of solutions of

subject to Pj < pj ≤ 2Pj. By Cauchy’s inequality,

    1. .

The first sum on the right side of (3.2) is equal to the total number of 23- tuples p1,...,p23 with Pj < pj ≤ 2Pj, while the second sum is bounded above by the integral on the left side of (2.3). Hence, appeals to the prime number theorem and
Lemma 1 yield
,
and the desired conclusion follows from our estimate for E23(n).

  1. Proof of Theorem 2

    1. Preliminaries. For the sake of simplicity, we present the case s = 23 in detail and then sketch the changes required in the proof of (1.4). Let N be a large parameter. We set and define P1,...,P22 by (3.1). We also write z = P15/79, L = logP, and X = PP1 ···P22N−1.

Recalling (2.15), we obtain
(4.1) )
, say.
When P < m ≤ 2P, the left side of (4.1) is equal to the indicator function of the primes, so the number of representations of n as the sum of 23 seventh powers of prime numbers is bounded below by the quantity
R(n) = X w(m),
m,p1,...,p22:(4.2)
where the summation is over the 23-tuples m,p1,...,p22 subject to
(m 7 + p71 + ··· + p722 = n,
(4.2)
P < m ≤ 2P, Pj < pj ≤ 2Pj.
We now introduce some notation needed in the application of the circle method. We write
,
Z
R(n;B) = h(α)f1(α)···f22(α)e(−αn)dα.
B
Further, let

where ω(u) is the function defined in Lemma 4. We define the singular series S(n) by
S .
S(n) is thoroughly studied in Chapter 8 of Hua [5]. In particular, Theorem 12 in [5] asserts that
(4.3) 1
for all odd n. The singular integral associated with R(n) is J(n) = J(n;∞), where
Z ξ
J(n;ξ) = v1(β)2v2(β)···v22(β)e(−βn) dβ.
ξ
Note that a routine application of the Fourier inversion formula yields
(4.4) .
Because of the presence of the sieve weights w(m), we also have to deal with a variant of J(n;ξ), namely,
Z ξ
J(n;ξ) = v(β;z)v1(β) ···v22(β)e(−βn) dβ.
ξ
Finally, we define the sets of major and minor arcs by M = M(P1/4,N) and m = [0,1] \M, respectively.
4.2.
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