I
5
= 5 x 5/(3+5) = 3.125 A
The total current passing through the resistance of 3Ω is then
=
I
2
+ I
5
= 2.5 + 3.125 =
5.625 A
Let us verify the solution using the basic nodal analysis referring to the node marked with V in
fig.(a).Then we get :
𝑉 − 20
5
+
𝑉
3
= 5
3V-60+5V=15
× 5
8V-60=75
8V=135
V=16.875
The current I passing through the resistance of
3Ω =
V/3 = 16.875/3 =
5.625 A .
Reciprocity theorem:
Under Basic Electrical Engineering In many electrical networks it is found that if
the positions of voltage source and ammeter are interchanged, the
reading of ammeter remains
the same. Suppose a voltage source is connected to a passive
network and an ammeter is
connected to other part of the network to indicate the response. Now any one interchanges the
positions of ammeter and voltage source that means he or she connects the voltage source at the
part of the network where the ammeter was connected and connects ammeter to that part of the
network where the voltage source was connected. The response of
the ammeter means current
through the ammeter would be the same in both the cases. This
is where the property of
reciprocity comes in the circuit. The particular circuit that has this reciprocal property, is called
reciprocal circuit.
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