I INTERNATIONAL SCIENTIFIC CONFERENCE OF YOUNG RESEARCHERS
Baku Engineering University
9
27-28 April 2018, Baku, Azerbaijan
bilir. Başqa sözlə riyaziyyat heç vaxt özü-özünə zidd gəlmir. Puankarenin təbirincə desək, riyaziyyat
insan kimi mükəmməldir, toplum isə natamamdır (7, s.267).
İSTİFADƏ OLUNMUŞ ƏDƏBİYYAT:
1.
Юшкевич А.П. Лейбниц и основание исчисления бесконечно малых // Успехи математических наук. 1948. Т. 3,
№ 1(23). — С. 150—165.
2.
Вейль Г. Математическое мышление. М., Наука, 1989.-400 с.
3.
Капра Ф. Дао физики. СПб., ОРИС, ЯНА-ПРИНТ. 1994. – 302 с.
4.
Уайтхед А.Н. Избранные работы по философии. М., Прогресс, 1990. – 720 с.
5.
Кассирер Э. Философия символических форм. Том 1. Язык. М., СПб, 2002. -272 с.
6.
Яглом И.М. Математика и реальный мир. М., КомКнига, 2007. - 64 с.
7.
Вечтомов Е.М. Метафизика математики. Киров, Изд-во ВятГГУ, 2006. - 508 с.
SPECTRAL ANALYSIS OF PT SYMMETRIC STURM-LIOUVILLE
EQUATION IN BUSH TYPE GRAPH
Rakib EFENDİEV
Baku Engineering University
refendiyev@beu.edu.az
AZERBAIJAN
Hidayet NUSRETZADE
Baku Engineering University
hidayet.1993@gmail.com
AZERBAIJAN
Sabina ALİYEVA
Baku Engineering University
s.aliyeva4728gmail.com
AZERBAIJAN
We investigate a generalization of the classical Hill problem with complex potentials to bush type
graph. Namelly , considered a graph
?????? in ℝ
6
with the set of edges
??????
0
,
??????
1
,
??????
2
,
??????
3
and the set of vertices
?????? ∪ ?????? where ?????? = {??????
1
, ??????
2
, ??????
3
} and ?????? = {??????
1
, ??????
2
, ??????
3
}.
The graph has the form
??????
0
∪ ?????? where ??????
0
is cycle,
??????
??????
∈ ??????
0
,
??????
??????
∉ ??????
0
,
?????? = 1,2,3. ?????? ∩ ??????
0
= ??????, and
?????? = ⋃
??????
??????
3
??????=1
,
??????
??????
= [??????
??????
, ∞], ??????
??????
∩ ??????
0
= ??????
??????
i.e all trees from
?????? have the common root ??????
??????
.
The cycle
??????
0
consist of three parts.
??????
0
= ⋃ ??????
??????
0
3
??????=1
, ??????
??????
0
= [??????
??????
, ??????
??????+1
], ?????? = 1, 2, 3.
??????
??????−1
= ??????
1
Each edge
??????
1
,
??????
2
,
??????
3
is viewed as a ray
[??????
??????
, ∞) and is parametrized by the parameter ??????
??????
??????[??????
??????
, ∞)
where the notation
??????
??????
with subscript j to denote the initial point 0 of the j
th
positive half axis is used.
Let d
o
be the length of
??????
??????
??????
. Then
??????
??????
= ??????
1
??????
+ ??????
2
??????
+ ??????
3
??????
Each part of
??????
??????
??????
, ?????? = 1,2,3 of ??????
??????
is parametrized by the parameter
??????
??????
??????[0, ??????
??????
??????
] where ??????
??????
= 0
corresponds to
??????
??????+1
.
We consider a family of PT – symmetric operators {
??????
??????
}, ?????? = 1,2,3,4 in ??????
2
[??????
??????
] , ?????? = 0,1,2,3 .
??????
3
??????
2
??????
1
??????
0
II INTERNATIONAL SCIENTIFIC CONFERENCE OF YOUNG RESEARCHERS
Baku Engineering University
10
27-28 April 2018, Baku, Azerbaijan
??????
??????
= −
??????
2
????????????
??????
2
+ ??????
??????
(??????
??????
), ??????
??????
(??????
??????
) = ∑ ??????
????????????
??????
??????????????????
??????
∞
??????=1
??????(??????
??????
) = {??????(??????
??????
), ??????????????????
0
∞
[??????
??????
]}.
We term the
spaces
??????
2
(Γ) and ??????(Γ) as follows
??????
2
(Γ) =
4
⨁
?????? = 1
??????
2
[??????
??????
] ??????(Γ) =
4
⨁
?????? = 1
??????
0
∞
[??????
??????
] ??????(Γ) ⊂ ??????
2
(Γ)
and we consider the operator
??????
Γ
on
??????(Γ)
??????
Γ
=
4
⨁
?????? = 1
??????
??????
In what follows, we study only extension defined by the following system of boundary conditions
at the nodes of the graph
1.
Ψ is continuous at the nodes of the graph.
2.
the sum of derivatives over all the branches emanating from a node, calculated for each node
is zero.
We solved the inverse problem, proved the uniqueness theorem and provided a constructive
procedure for the solution of the inverse problem.
RANDOM WALK
Kamala DADASHOVA
Baku Engineering University
kamaladadashova1995@gmail.com
AZERBAIJAN
Humbet ALIEV
Baku Engineering University
hualiyev@beu.edu.az
AZERBAIJAN
ABSTRACT
Nowadays theory of probability is widely used in different fields of reseach areas. And one of the branches of this
theory- random walk has an important role not in mathematics but also in other sciences. The main characteristics and some
aplication of this theory is considered in this thesis.
Keywords and phrases: probability, random walk, Brownian motion, success, failure, expectation
The first use of of the concept “random walk” emerged in a note to “Nature” by Karl Pearson in
1905, in the form of question: “ A man starts from a point 0 and walks l yards in a straight line ; he
then turns through any angle whatever and walks another l yards in a straight line.He then repeats this
process n times.I require the probability that after these n stretches he is at a distance between r and
?????? + ?????? ∙ ?????? from his starting point 0.”Lord Rayleigh was one of the Pearson’s respondents, whose
assistance led Pearson to conclude that “the most probable place to find drunken man who is at all
capable of keeping on his feet is somewhere near his starting point.” The random walk ,also called as
Drunkard’s walk ,is the main part of probability theory and still has inseperable part of mathematics.
Random walks have applications to many scientific fields including ecology,psychology,computer
science ,physics, biology and economics.
Basic example of random walk is the random walk on the integer number line,Z which sometimes
called as one-dimensional random walk.If we draw number line and denote integers as a position that
drunken man stand on , then we can easily find the probability of each position this man can be on
given t time. If
0
t
,the only position man stand at is
0
x
,therefore
1
)
(
x
P
.For
1
t
, the man can
go either -1 or +1,therefore the probability of being
1
x
is
2
1
P
,
1
x
is
2
1
P
, and
0
x
is
0
P
.For
2
t
,the probability of possible position is
2
x
,
2
x
,
0
x
and their probability
2
1
P
,
2
1
P
,
4
1
P
,respectively.We can interpret this result by means of tree algorithm illustrated
below.